Maths QUestion please?

(a)
Since the required line is parallel to 2x - 5y + 3 = 0,
then let 2x - 5y + a = 0 be the required line.

The required line passes through (1, 3).
Substitute x = 1 and y = 3 into the equation 2x - 5y + a = 0 :
2(1) - 5(3) + a = 0
a = 13

The equation of the required line is :
2x - 5y + 13 = 0


(b)
Since the required line is parallel to 2x - 5y + 3 = 0,
then let 2x - 5y + b = 0 be the required line.

The required line passes through (0, 0).
Substitute x = 0 and y = 0 into the equation 2x - 5y + b = 0 :
2(0) - 5(0) + b = 0
a = 0

The equation of the required line is :
2x - 5y = 0


(c)
Since the required line is parallel to 2x - 5y + 3 = 0,
then let 2x - 5y + c = 0 be the required line.

The required line passes through (-3, 2).
Substitute x = -3 and y = 2 into the equation 2x - 5y + c = 0 :
2(-3) - 5(2) + c = 0
c = 16

The equation of the required line is :
2x - 5y + 16 = 0

a) 2x-5y-(2×1-5×3)=0, which simplifies to 2x-5y+13=0
b) 2x-5y-(2×0-5×0)=0, which simplifies to 2x-5y+0=0
c) 2x-5y-(2×-3-5×2)=0, which simplifies to 2x-5y+16=0

https://www.desmos.com/calculator/jm6toigbba - Graph

nah