How do I factor each polynomial, using gcf: 3p^2-75?
回答 (6)
2017-02-10 3:56 am
✔ 最佳答案
First factor out the common 3 from both terms:3(p² - 25)
Now use the difference of squares factoring --> a² - b² = (a - b)(a + b)
a = p
b = 5
Answer:
3(p - 5)(p + 5)
2017-02-10 3:55 am
3 [ p² - 25 ]
3 [ p - 5 ] [ p + 5 ]
3 [ p - 5 ] [ p + 5 ]
2017-02-10 9:04 am
3p^2-75 = 0
3 p ^ 2 = 75
p ^ 2 = 25
p = 5 , - 5
(p + 5) (p - 5)
3 p ^ 2 = 75
p ^ 2 = 25
p = 5 , - 5
(p + 5) (p - 5)
2017-02-10 4:32 am
3(p^2 - 5^2)
= 3(p + 5)(p - 5)
= 3(p + 5)(p - 5)
2017-02-10 3:56 am
3p^2 - 75 =
3(p^2 - 25) =
3(p - 5)(p + 5)
3(p^2 - 25) =
3(p - 5)(p + 5)
2017-02-10 3:55 am
a^2 - b^2 = (a-b)(a+b)
收錄日期: 2021-04-24 00:14:00
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