find the principal argument of 1+2i/1-(1-i)^2?
回答 (1)
2017-02-08 4:04 pm
✔ 最佳答案
(1 + 2i) / [1 - (1 - i)²]= (1 + 2i) / [1 - (1 - 2i + i²)]
= (1 + 2i) / [1 + 2i]
= 1 + 0i
cosφ = 1 and sinφ = 0
where φ is the argument.
Hence, principal argument = 0
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20170208074251AAAKrru