Y=8cos^-1(sin 2x) Dy/dx and simplify?
回答 (1)
2017-02-07 7:38 pm
✔ 最佳答案
y = 8cos⁻¹(sin 2x)Using chain rule, dy / dx
= d[8cos⁻¹(sin 2x)] / dx
= {d[8cos⁻¹(sin 2x)] / d(sin 2x)} * {d(sin 2x) / d(2x)} * [d(2x) / dx]
= [8 / √(1 - sin² 2x)] * (sin 2x) * 2
= 16 sin 2x / √(1 - sin² 2x)
= 16 sin 2x / √(cos² 2x)
= 16 sin 2x / cos 2x
= 16 tan 2x
收錄日期: 2021-04-18 16:03:41
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https://hk.answers.yahoo.com/question/index?qid=20170207101604AAVefvD