✔ 最佳答案
Assuming the connecting rod is massless and the rod is initially horizontal:
moment of inertia
I = mx² + 2m(2x)² = 9mx²
initial torque
τ = (2m*2x - m*x)*g = 3mxg
and so the initial acceleration
α = τ / I = 3mxg / 9mx² = g / 3x
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