A sample contains 9.81g zn, 1.8(10)rais to power 23 atoms of cr and 0.6 g-atoms of oxygen. what is its empherical formullah?
回答 (1)
2017-02-03 1:32 am
Molar mass of Zn = 65.4 g/mol
Avogadro constant = 6.0 × 10²³ /mol
Mole ratio Zn : Cr : O
= (9.81/65.4) : [(1.8 × 10²³)/(6.0 × 10²³)] : 0.6
= 0.15 : 0.3 : 0.6
= 1 : 2 : 4
Empirical formula = ZnCr₂O₄
Avogadro constant = 6.0 × 10²³ /mol
Mole ratio Zn : Cr : O
= (9.81/65.4) : [(1.8 × 10²³)/(6.0 × 10²³)] : 0.6
= 0.15 : 0.3 : 0.6
= 1 : 2 : 4
Empirical formula = ZnCr₂O₄
收錄日期: 2021-04-18 16:04:33
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