What mass of SOCl2 can be prepared by heating SO2 gas with the quantity of PCl5 that contains 3.01 x 1023 Cl atoms? The balanced equation for the reaction is:
SO2 (g) + PCl5 (s) POCl3 (l) + SOCl2 (l)
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chemistry homework?
2017-01-30 10:19 pm
回答 (1)
2017-01-30 11:06 pm
SO₂(g) + PCl₅(s) → POCl₃(l) + SOCl₂(l)
No. of moles of Cl atoms in PCl₅ = (3.01 × 10²³ atoms) / (6.02 × 10²³ atoms/mol) = 0.5 mol
1 mole of PCl₅ contains 5 moles of Cl atoms.
No. of moles of PCl₅ reacted = (0.5 mol) × (1/5) = 0.1 mol
According to the above equation, mole ratio PCl₅ : SOCl₂ = 1 : 1
No. of moles of SOCl₂ prepared = 0.1 mol
Molar mass of SOCl₂ = (32.1 + 16.0 + 35.5×2) g/mol = 119.1 g/mol
Mass of SOCl₂ prepared = (0.1 mol) × (119.1 g/mol) = 11.9 g
No. of moles of Cl atoms in PCl₅ = (3.01 × 10²³ atoms) / (6.02 × 10²³ atoms/mol) = 0.5 mol
1 mole of PCl₅ contains 5 moles of Cl atoms.
No. of moles of PCl₅ reacted = (0.5 mol) × (1/5) = 0.1 mol
According to the above equation, mole ratio PCl₅ : SOCl₂ = 1 : 1
No. of moles of SOCl₂ prepared = 0.1 mol
Molar mass of SOCl₂ = (32.1 + 16.0 + 35.5×2) g/mol = 119.1 g/mol
Mass of SOCl₂ prepared = (0.1 mol) × (119.1 g/mol) = 11.9 g
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