國中二年級數學,因式分解 X平方-Y平方+2Y-1 =?

2017-01-29 9:42 pm

回答 (4)

2017-01-29 10:17 pm

✔ 最佳答案

x²- y² + 2y -1
= x²- (y² - 2y +1)
= x²- (y - 1)²
= [x+(y-1)] [x-(y-1)] . . . . . . . . < ∵ A²- B² = (A+B)(A-B) >
= (x+y-1) (x-y+1)

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2017-02-04 9:12 am

X^2-(Y-1)^2
=(X-Y+1)(X+Y-1)

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2017-01-31 4:47 pm

很簡單
x²- y² + 2y -1
= x²- (y² - 2y +1)
= x²- (y - 1)²
= [x+(y-1)] [x-(y-1)] . . . . . . . . < ∵ A²- B² = (A+B)(A-B) >
= (x+y-1) (x-y+1)

參考: 自己

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2017-01-30 11:45 pm

x²-y²+2y-1
=x²-(y²-2y+1)
=x²-(y-1)²
=(x+y-1)(x-y+1)

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