(5x-4)/x^2+8x+12
i need to make the denominator
6x(x+6)(x+2)
x+7/3x-15
the denominator needs to be 3(X-5)(X+12)
Build the following rational expression into an equivalent expression with the given denominator.?
2017-01-29 12:30 pm
回答 (2)
2017-01-29 12:46 pm
✔ 最佳答案
(5x-4)/(x²+8x+12)= (5x-4)/(x+6)(x+2)
= 6x(5x-4) / 6x(x+6)(x+2)
(x+7) /(3x-15)
= (x+7) / 3(x-5)
= (x+7)(x+12) / 3(x-5)(x+12)
2017-01-29 6:11 pm
(5x – 4)/(x² + 8x +12)
Deno: (x² + 8x +12) = 0
x² + 6x + 2x + 12 = 0
x (x + 6) + 2 (x + 6) = 0
(x + 6) (x + 2) = 0
X = -6, x = -2
(5x - 4)/(x + 6) (x + 2).
Deno: (x² + 8x +12) = 0
x² + 6x + 2x + 12 = 0
x (x + 6) + 2 (x + 6) = 0
(x + 6) (x + 2) = 0
X = -6, x = -2
(5x - 4)/(x + 6) (x + 2).
收錄日期: 2021-04-24 00:14:32
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20170129043010AAB861y