What is the mass of 8.50 × 1022 molecules of NH3?
回答 (1)
2017-01-29 1:21 am
Avagadro constant = 6.02 × 10²³ /mol
No. of moles of NH₃ = (8.50 × 10²²) / (6.02 × 10²³ /mol) = 0.141 mol
Molar mass of NH₃ = (14.0 + 1.0×3) g/mol = 17.0 g/mol
Mass of NH₃ = (0.141 mol) × (17.0 g/mol) = 2.40 g (3 sig. sig.)
No. of moles of NH₃ = (8.50 × 10²²) / (6.02 × 10²³ /mol) = 0.141 mol
Molar mass of NH₃ = (14.0 + 1.0×3) g/mol = 17.0 g/mol
Mass of NH₃ = (0.141 mol) × (17.0 g/mol) = 2.40 g (3 sig. sig.)
收錄日期: 2021-04-18 16:04:42
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20170128165525AARNU0O