What is the initial temperature of the titanium?
2017-01-24 5:04 pm
A sample of solid titanium is heated with an electrical coil. If 76.4 Joules of energy are added to a 12.6 gram sample and the final temperature is 36.1°C.
回答 (2)
2017-01-24 6:00 pm
Let T°C be the final temperature of the titanium sample.
Refer to: https://en.wikipedia.org/wiki/Heat_capacities_of_the_elements_(data_page)
Specific heat of titanium, c = 0.523 J/(g°C)
Heat gain of the titanium sample, E = 76.4 J
Mass of the titantium sample, m = 12.6 g
Temperature change of the titanium sample, ΔT = (36.1 - T)°C
E = m c ΔT
76.4 = 12.6 × 0.523 × (36.1 - T)
36.1 - T = 11.6
T = 24.5
The initial temperature of the titanium sample = 24.5°C
Refer to: https://en.wikipedia.org/wiki/Heat_capacities_of_the_elements_(data_page)
Specific heat of titanium, c = 0.523 J/(g°C)
Heat gain of the titanium sample, E = 76.4 J
Mass of the titantium sample, m = 12.6 g
Temperature change of the titanium sample, ΔT = (36.1 - T)°C
E = m c ΔT
76.4 = 12.6 × 0.523 × (36.1 - T)
36.1 - T = 11.6
T = 24.5
The initial temperature of the titanium sample = 24.5°C
2017-01-24 6:01 pm
You have:
------------------
Q = Delta U = ( m ) ( Cv ) ( T2 - T1 )
T2 - T1 = Q / ( m ) ( Cv )
T1 = T2 - Q / ( m ) ( Cv )
T1 = 36.1 C - ( 76.4 J ) / ( 12.6 g ) ( 0.522 J/ g - C deg )
T1 = 36.1 C - 11.6 C deg = 24.5 C <---------------------------
------------------
Q = Delta U = ( m ) ( Cv ) ( T2 - T1 )
T2 - T1 = Q / ( m ) ( Cv )
T1 = T2 - Q / ( m ) ( Cv )
T1 = 36.1 C - ( 76.4 J ) / ( 12.6 g ) ( 0.522 J/ g - C deg )
T1 = 36.1 C - 11.6 C deg = 24.5 C <---------------------------
收錄日期: 2021-05-01 13:43:02
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https://hk.answers.yahoo.com/question/index?qid=20170124090422AABRkwI