A 10.0 mL sample of sulfuric acid was titrated with 38.72 mL of 0.148M Sodium Hydroxide. SEE THE REST OF THE QUESTION.?

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2017-01-18 12:01 pm

更新1:

The balanced chemical equation is: H2SO4 + 2NaOH -----> Na2SO4 + 2H2O What is the Molarity of the sulfuric acid solution? What I am struggling with, is how to determine what I need to solve for. Do I solve for the 10.0 mL? or do I solve for the total volume of 48.72 mL (38.72mL NaOH added) and calculate the Molarity from there? Please help, I am stumped and need a bit of guidance. Thanks!

回答 (1)

wanszeto

2017-01-18 12:47 pm

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

No. of moles of NaOH reacted = (0.148 mol/L) × (38.72/1000 L) = 0.00573 mol

According to the equation, mole ratio H₂SO₄ : NaOH = 1 : 2
No. of moles of H₂SO₄ reacted = 0.00573 × 2 = 0.0115 mol

Molarity of H₂SO₄ = (0.0115 mol) / (10.0/1000 L) = 1.15 M

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