PRE CALC HELP!!!!?

6 / (3x + 2) ≥ 0
3x + 2 > 0
3x > -2
x > -2/3

(When 3x + 2 = 0, the fraction 6/0 is undefined.)

phuck you all idiots

is it 6/(3x + 2) ≥ 0 ?

6 / (3x +2) > 0
This happens whenever 3x +2 > 0
x > -2/3
6 / (3x + 2) = 0
This cannot happen.

6/3x simplifies to 2x...2x >= -2....x = -1

Presentation is unclear.
Brackets required.

6/ (3x) + 2 ≥ 0
multiply both sides by 3x
6 + 6x ≥ 0
subtract 6 from both sides
6x ≥ -6
divide both sides by 6
x ≥ -1

[-1, infinity) is the solution

6/3x + 2 ≥ 0 means (6/3)x + 2 ≧ 0 .
2x + 2 ≧ 0
2x ≧ -2
x ≧ -1 ---> [-1 , ∞)

If you want to mean 6/(3x) + 2 ≧ 0 , it means 6/(3x) ≧ -2 , clearly x ≠ 0 .
Case1 . x > 0
6 ≧ -2*(3x)
6 ≧ -6x
-1 ≦ x
It must be x > 0 , so x > 0 .
Case2. x < 0
6 ≦ -2*(3x)
6 ≦ -6x
-1 ≧ x
It must be 0 < x , so x ≦ -1 .
Therefore , x ≦ -1 or x > 0 . ---> (-∞ , -1] ∪ (0 , ∞)

I will do it different that above since you did not have parenthesis.

6/x + 2 >/= 0 ................. subtract 2

..... 6/x >/= - 2 .............. multiply by x .............. x not= 0

......... 6 >/= -2x ............. divide by ( - 2)

....... -3 >/= x....... OR

........ x </= - 3 ............... OR ...... x = ( - oo , -3 ] ...... ANSWER

6/3x + 2 ≥ 0
6 + 6x ≥ 0
6x ≥ -6
x ≥ -1