✔ 最佳答案
C₇H₅N₃O₆(s) → (3/2)N₂(g) + (5/2)H₂(g) + 3O₂(g) + 7C(s)
For each mole of trinitrotoluene (C₇H₅N₃O₆) decomposed :
No. of moles of gases formed = [(3/2) + (5/2) + 3] = 7 mol
Work = Δ(PV) = Δ(nRT) = RT Δn = [8.314 J/(mol K)] × (307.95 K) × (7 mol) = 17920 J = 17.92 kJ