What is the work associated with decomposition of trinitrotoluene (TNT) upon detonation according to the following reaction at 307.95 K?

2017-01-17 1:22 am
C7H5N3O6(s)⟶3/2N2(g)+5/2H2(g)+3O2(g)+7C(s)

回答 (2)

2017-01-17 1:39 am
✔ 最佳答案
C₇H₅N₃O₆(s) → (3/2)N₂(g) + (5/2)H₂(g) + 3O₂(g) + 7C(s)

For each mole of trinitrotoluene (C₇H₅N₃O₆) decomposed :
No. of moles of gases formed = [(3/2) + (5/2) + 3] = 7 mol
Work = Δ(PV) = Δ(nRT) = RT Δn = [8.314 J/(mol K)] × (307.95 K) × (7 mol) = 17920 J = 17.92 kJ
2017-01-17 1:55 am
All carbohydrates, including all monosaccharides (C₆H₁₂O₆), disaccharides (C₁₂H₂₂O₁₁) and polysaccharides (C₆(H₂O)₅n), have the mole ratio H : O = 2 : 1.

Also, my other compounds (such as methanal (HCHO), acetic acid (CH₃COOH), propanedial (CH₂(CHO)₂), etc.) have the mole ratio H : O = 2 : 1.


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