Suppose x ∈ R and |x| ≤ 1. Prove that |x^2−4| ≤ 3|x−2|?
回答 (1)
|x| < 1
-1 < x < 1
x < 1
x+2 < 3
|x^2-4| = |(x-2)(x+2)| = |x-2||x+2| <= 3 |x-2|
收錄日期: 2021-05-01 20:54:34
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20170116132338AAww08m
檢視 Wayback Machine 備份