Calculate the amount of energy required to vaporize 1.97 mol of dihydrogen monoxide given the molar enthalpy of vaporization?

👨🏻‍🏫 學術台化學

[匿名]

2017-01-12 7:57 pm

ΔH°vap is 40.67 kJ mol^-1.

回答 (1)

wanszeto

2017-01-12 8:09 pm

The amount of energy required
= (40.67 kJ mol⁻¹) × (1.97 mol)
= 80.1 kJ
(3 sig. fig.)

👍 2 👎 1