The reaction 2 NO(g) + O2(g) --> 2 NO2(g) is important in forming smog. Under certain conditions, the rate law for a the reaction is
rate = 4.0 x 10-3 1/M2*s * [NO]2* [O2]
What is the rate when [NO]=0.020 M and [O2]=0.035 M?
a.
5.6 x 10-2 M/s
b.
9.8 x 10-5 M/s
c.
9.8 x 10-8 M/s
d.
9.8 x 10-2 M/s
e.
5.6 x 10-8 M/s.
The reaction 2 NO(g) + O2(g) --> 2 NO2(g) is important in forming smog. Under certain conditions, the rate law for a the reaction is?
2017-01-11 11:22 am
回答 (1)
2017-01-11 12:28 pm
2 NO(g) + O₂(g) → 2 NO₂(g)
rate = (4.0 × 10⁻³ 1/M²s) [NO]² [O₂]
When [NO]=0.020 M and [O2]=0.035 M :
rate = (4.0 × 10⁻³) × (0.020)² × (0.035) M/s = 5.6 × 10⁻⁸ M/s
The answer: 5.6 × 10⁻⁸ M/s
rate = (4.0 × 10⁻³ 1/M²s) [NO]² [O₂]
When [NO]=0.020 M and [O2]=0.035 M :
rate = (4.0 × 10⁻³) × (0.020)² × (0.035) M/s = 5.6 × 10⁻⁸ M/s
The answer: 5.6 × 10⁻⁸ M/s
收錄日期: 2021-04-18 15:56:56
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https://hk.answers.yahoo.com/question/index?qid=20170111032241AAkYHxD