A student placed 16.5 g of glucose (C6H12O6) in a volumetric flask?
2017-01-11 12:42 am
added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100L.- mark on the neck of the flask was reached. The flask was then shaken until the solution was uniform. A 50.0mL- sample of this glucose solution was diluted to 0.500L . How many grams of glucose are in 100.mL of the final solution?
回答 (4)
2017-01-16 9:10 am
✔ 最佳答案
Initial solution = 16.5 g/100 ml = 0.165 gm/ml 0.165 g/ml x 50 ml = 8.25 gms placed into 0.5 L.
8.25 g/500 ml x 100 mls = 1.65 gms in the 100 mls
2017-01-11 1:08 am
When 16.5 g of glucose dissolves to form 100 L of solution :
Concentration = (16.5 g) / (100 L) = 0.165 g/L
When 50.0 mL of the above solution is diluted to 0.500 L (500 mL), dilution factor is 50/500.
Concentration of final solution = (0.165 g/L) × (50/500) = 0.0165 g/L
Mass of glucose in 100 mL (0.100 L) of the final solution = (0.0165 g/L) × (0.100 L) = 0.00165 g
Concentration = (16.5 g) / (100 L) = 0.165 g/L
When 50.0 mL of the above solution is diluted to 0.500 L (500 mL), dilution factor is 50/500.
Concentration of final solution = (0.165 g/L) × (50/500) = 0.0165 g/L
Mass of glucose in 100 mL (0.100 L) of the final solution = (0.0165 g/L) × (0.100 L) = 0.00165 g
2017-01-11 12:46 am
16.5 / 100 = x / 50
x = 8.25
8.25/500 = x / 100
x = 1.65g <<< answer
x = 8.25
8.25/500 = x / 100
x = 1.65g <<< answer
2017-01-11 12:43 am
bi
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