第一和二題有關三角函數?

2017-01-07 12:45 am

回答 (1)

2017-01-07 8:03 am
✔ 最佳答案
Sol
1
SinA/(1-CosA)+(1-CosA)/SinA
=SinA(1+CosA)/(1-CoA^2 A)+(1-CosA)/SinA
=SinA(1+CosA)/Sin^2 A+(1-CosA)/SinA
=(1+CosA)/SinA+(1-CosA)/SinA
=2/SinA
=2CscA
2
[(1+SimA)/(1+CosA)]*[(1+SecA)/(1+CscA)]
=[(1+SinA)/(1+CosA)]*[(1+1/CosA)/(1+1/SinA)]
=CosA/SinA*[(1+SinA)/(1+CosA)]*[(1+1/CosA)/(1+1/SinA)]/(SinA/CosA)
=[(1+SinA)/(1+CosA)]*[(CosA+1)/(SinA+1)]/(SinA/CosA)
=SinA/CosA
=TanA


收錄日期: 2021-04-30 22:14:15
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