IF solubiltiy of BaSO4 in water is 8 8 10^-4 mol dm^-3, calculate its solubility in 0.01 mol dm^-3 of H2SO4?

2017-01-01 4:45 pm

IF solubiltiy of BaSO4 in water is 8 * 10^-4 mol dm^-3, calculate its solubility in 0.01 mol dm^-3 of H2SO4

Please explain in detail step by step with the formulae used

回答 (1)

戇戇居士

2017-01-01 8:14 pm

Let s mol dm⁻³ be the solubility of BaSO₄ in 0.01 mol dm⁻³ of H₂SO₄.

BaSO₄(s) + aq ⇌ Ba²⁺(aq) + SO₄²⁻(aq) …. Ksp
Ksp = [Ba²⁺] [SO₄²⁻]

In water :
Ksp = (8 × 10⁻⁴) × (8 × 10⁻⁴) = 6.4 × 10⁻⁷ …… {1}

In 0.01 0.01 mol dm⁻³ of H₂SO₄ :
Ksp = s × 0.01 = 0.01s …… {2}

Compare {1} and {2}.
At fixed temperature, Ksp is constant.
0.01s = 6.4 × 10⁻⁷
s = 6.4 × 10⁻⁵

Solubility of BaSO₄ in 0.01 mol dm⁻³ of H₂SO₄ = 6.4 × 10⁻⁵ mol dm⁻³

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