彰師大105年度離散數學
第4題
彰師大105年度離散數學問題4?
回答 (1)
2016-12-22 1:53 pm
x0 = 3
x1 = (1+4*3) mod 7 = 13 mod 7 = 6
x2 = (1+4*6) mod 7 = 25 mod 7 = 4
x3 = (1+4*4) mod 7 = 17 mod 7 = 3
x4 = (1+4*3) mod 7 = 6 = x1
x5 = x2 = 4
⇒ x_(n+3) = x_n
x1 = (1+4*3) mod 7 = 13 mod 7 = 6
x2 = (1+4*6) mod 7 = 25 mod 7 = 4
x3 = (1+4*4) mod 7 = 17 mod 7 = 3
x4 = (1+4*3) mod 7 = 6 = x1
x5 = x2 = 4
⇒ x_(n+3) = x_n
收錄日期: 2021-04-11 21:33:43
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20161221091029AA4Rq3i