cscθ
Cosθ
Tanθ
更新1:
Find exact value
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2016-12-20 1:53 am
Suppose that θ is a angle in standard position whose terminal side intersects the unit circle at ( -5/13, -12/13)
cscθ
Cosθ
Tanθ
cscθ
Cosθ
Tanθ
回答 (2)
2016-12-20 2:21 am
On the unit circle:
sinθ = y = −12/13
cosθ = x = −5/13
tanθ = y/x = 12/5
cscθ = 1/sinθ = −13/12
2016-12-20 2:01 am
Since this is a unit circle, r = 1
sin(θ) = (-12/13) / 1 = -12/13
csc(θ) = 1/sin() = 1/(-12/13) = -13/12
cos(θ) = (-5/13)/1 = -5/13
tan(θ) = y/x = (-12/13) / (-5/12) = 12/5 = 2.4
sin(θ) = (-12/13) / 1 = -12/13
csc(θ) = 1/sin() = 1/(-12/13) = -13/12
cos(θ) = (-5/13)/1 = -5/13
tan(θ) = y/x = (-12/13) / (-5/12) = 12/5 = 2.4
收錄日期: 2021-04-23 23:57:07
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20161219175326AABhtu6