A graph of a quadrant function with vertex (3,-2)... what would be the domain and range?
回答 (1)
2016-12-20 1:10 am
✔ 最佳答案
Assuming "quadrant" should be "quadratic," it depends which way the parabola opens.y = a(x - 3)^2 - 2 with a > 0
domain is all real numbers
range is [-2, ∞)
y = a(x - 3)^2 - 2 with a < 0
domain is all real numbers
range is (-∞, -2]
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