help please?

👨🏻‍🏫 學術台數學

[匿名]

2016-12-20 12:37 am

Functions s and t defined as follows

s(x)=-x-2

t(x)=2x^2+1

Find the value of s(t(2))

回答 (5)

[匿名]

2016-12-20 12:45 am

✔ 最佳答案

First evaluate t(2)

2(2)^2+1 =9

Now using that value, evaluate the "s" function

-9-2= -11

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Como

2016-12-20 7:11 am

t (2) = 9
s (9) = - 9 - 2 = - 11

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lenpol7

2016-12-20 1:23 am

s(t(x)) = -(2x^2 + 1) - 2
s(t(x)) = -2x^2 - 1 - 2
s(t(x)) = -2x^2 - 3
s(t(2)) = -2(2)^2 - 3 => -8 - 3 = -11
s(t(2)) = -11

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[匿名]

2016-12-20 12:43 am

For every x in s(x) plug in the t(x) function. So we get -(2x^2+1)-2 Plug in 2 into the equation and the answer is -11

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[匿名]

2016-12-20 12:41 am

s(t(2)) = s(2*2^2 + 1)

= s(9)

= - 9 - 2

= - 11

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