How many equivalents are in 12.0 mL of 0.16 M Ba(OH)2 solution?
回答 (1)
2016-12-13 4:05 pm
No. of moles of Ba(OH)₂ = (0.16 mol/L) × (12.0/1000 L) = 0.00192 mol
1 mole of Ba(OH)₂ contains 2 moles of OH⁻ ions which can neutralize 2 moles of H⁺ ions.
No. of equivalents of Ba(OH)₂ = 0.00192 × 2 = 0.00384
1 mole of Ba(OH)₂ contains 2 moles of OH⁻ ions which can neutralize 2 moles of H⁺ ions.
No. of equivalents of Ba(OH)₂ = 0.00192 × 2 = 0.00384
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