若x^2-10x+25-4y^2=(x+2y-5)(x+ay+b)則2a-b為?因式分解x^3-3x^2-4x+12=?因式分解12x^2+13x(x+1)-14(x+1)^2=?已知2014=2*19*53設x^2-15x-2014=(x+a)(x+b)且0>b則a-b之值為?

2016-12-10 11:50 pm

回答 (1)

2016-12-11 12:08 am
✔ 最佳答案
1 若x^2-10x+25-4y^2=(x+2y-5)(x+ay+b)則2a-b為?
Sol
(x+2y-5)(x+ay+b)
=x(x+ay+b)+2y(x+ay+b)-5(x+ay+b)
=(x^2+axy+bx)+(2xy+2ay^2+2by)+(-5x-5ay-5b)
=x^2+(a+2)xy+2ay^2+(b-5)x+(2b-5a)y-5b
a+2=0,2a=-4,b-5=-10,2b-5a=0,-5b=25
a=-2
b=-5
2a-b=-4+5=1
2 因式分解x^3-3x^2-4x+12=?
Sol
x^3-3x^2-4x+12
=(x^3-3x^2)+(-4x+12)
=x^2(x-3)-4(x-3)
=(x^2-4)(x-3)
=(x-2))(x+2)(x-3)
3 因式分解12x^2+13x(x+1)-14(x+1)^2=?
Sol
12x^2+13x(x+1)-14(x+1)^2
=12x^2+13x^2+13x-14x^2-28x-14
=11x^2-15x-14
=(11x+7)(x-2)
4 已知2014=2*19*53設x^2-15x-2014=(x+a)(x+b)且0>b則a-b之值為?
Sol
2014=2*19*53=38*53
53-38=15
x^2-15x-2014
=(x^2-53x)+(38x-2014)
=x(x-53)+38(x-53)
=(x+38)((x-53)
a=38-b=-53
a-b=38+53=91


收錄日期: 2021-04-30 22:09:43
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