lim x→−∞ (8x-3)/((√4x^2+1))?

2016-12-10 7:23 pm

回答 (1)

2016-12-10 7:27 pm
✔ 最佳答案
Sol
lim(x->∞)_(8x-3)/√(4x^2+1)
= lim(x->∞)_8x)/√(4x^2)
= lim(x->∞)_8x)/(2x)
=4


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