lim x→−∞ (8x-3)/（(√4x^2+1)）?
回答 (1)
2016-12-10 7:27 pm
✔ 最佳答案
Sollim(x->∞)_(8x－3)/√(4x^2+1)
= lim(x->∞)_8x)/√(4x^2)
= lim(x->∞)_8x)/(2x)
=4
收錄日期: 2021-04-18 15:54:11
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20161210112340AA0Rrty