A sample of methane (CH4) has a volume of 29 mL at a pressure of 0.90 atm . What is the final volume, in milliliters, of the gas at each of the following pressures, if there is no change in temperature and amount of gas?
a)0.27 atm
b)2.90 atm
C)2700 mmHg
D)64.0 torr
Chemistry Help?
2016-12-08 1:55 am
回答 (1)
2016-12-08 2:47 pm
a)
(29 mL) x (0.90 atm / 0.27 atm) = 97 mL
b)
(29 mL) x (0.90 atm / 2.90 atm) = 9.0 mL
c)
(29 mL) x (0.90 atm / ((2700 mmHg) / (760 mmHg/atm)) = 7.3 mL
d)
(29 mL) x (0.90 atm / ((64.0 torr / (760 torr/atm)) = 310 mL
(29 mL) x (0.90 atm / 0.27 atm) = 97 mL
b)
(29 mL) x (0.90 atm / 2.90 atm) = 9.0 mL
c)
(29 mL) x (0.90 atm / ((2700 mmHg) / (760 mmHg/atm)) = 7.3 mL
d)
(29 mL) x (0.90 atm / ((64.0 torr / (760 torr/atm)) = 310 mL
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