有三个自然数A,B,C,已知A*B=630;B*C=1323;A*C=210。问这三个自然数的和是多少?

2016-12-07 11:57 am

回答 (2)

2016-12-07 12:29 pm
✔ 最佳答案
( ABC )² = AB * BC * AC = 630*1323*210 = 175032900
ABC = √175032900 = 13230

A = ABC / ( BC ) = 13230 / 1323 = 10
B = ABC / ( AC ) = 13230 / 210 = 63
C = ABC / ( AB ) = 13230 / 630 = 21
三數和 = 10 + 63 + 21 = 94

Ans: 94
2016-12-09 12:57 pm
A*B=630;A*C=210:B=3C
B*C=1323:3C*C=1323:C = 21
B=3C = 63
A*C=210 : A = 10
和 = 10+63+21 = 94

有三个自然数A,B,C,已知A*B=630;B*C=1323;A*C=210。问这三个自然数的和是多少?


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