if sinθ =2/sqrt5 what are 2 possible angles between 0 and 360?
回答 (4)
sin Ө = 2 / √5________quadrants 1 and 2
Ө = 23.6⁰ , 156.4⁰
sinθ = 2/√5
θ₁ = arcsin(2/√5) ≅ 63.4°
θ₂ = 180-63.4 ≅ 116.6°
sinθ =2/sqrt(5)
θ = 63.43, 116.57
收錄日期: 2021-04-23 23:54:25
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