if sinθ =2/sqrt5 what are 2 possible angles between 0 and 360?
回答 (4)
2016-12-05 9:55 pm
sin Ө = 2 / √5________quadrants 1 and 2
Ө = 23.6⁰ , 156.4⁰
Ө = 23.6⁰ , 156.4⁰
2016-12-05 8:47 pm
sinθ = 2/√5
θ₁ = arcsin(2/√5) ≅ 63.4°
θ₂ = 180-63.4 ≅ 116.6°
θ₁ = arcsin(2/√5) ≅ 63.4°
θ₂ = 180-63.4 ≅ 116.6°
2016-12-05 8:44 pm
sinθ =2/sqrt(5)
θ = 63.43, 116.57
θ = 63.43, 116.57
2016-12-05 8:38 pm
Dh
收錄日期: 2021-04-23 23:54:25
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20161205123809AAXQcto