Plz help Fe2O3(s) + CO(g) Fe(l) + CO2(g) How many grams of Fe2O3(s) will be required to produce 1.20 moles of Fe(l) in the above reaction?
回答 (1)
2016-12-02 5:00 pm
Molar mass of Fe = 55.85 g/mol
Molar mass of Fe₂O₃ = (55.85×2 + 16.00×3) g/mol = 159.7 g/mol
Fe₂O₃(s) + 3CO(g) → 2Fe(l) + 3CO₂(g)
OR: Mole ratio Fe₂O₃ : Fe = 1 : 2
No. of moles of Fe reacted = 1.20 mol
No. of moles of Fe₂O₃ required = (1.20 mol) × (1/2) = 0.600 mol
Mass of Fe₂O₃ required = (0.600 mol) × (159.7 g/mol) = 95.8 g
Molar mass of Fe₂O₃ = (55.85×2 + 16.00×3) g/mol = 159.7 g/mol
Fe₂O₃(s) + 3CO(g) → 2Fe(l) + 3CO₂(g)
OR: Mole ratio Fe₂O₃ : Fe = 1 : 2
No. of moles of Fe reacted = 1.20 mol
No. of moles of Fe₂O₃ required = (1.20 mol) × (1/2) = 0.600 mol
Mass of Fe₂O₃ required = (0.600 mol) × (159.7 g/mol) = 95.8 g
收錄日期: 2021-04-18 15:50:56
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