Discrete Math Proof?
2016-12-01 8:00 pm
Im doing an inductive proof, and I got stuck on showing how (k+1)*2^(k+1) +(k-1)*2^(k+1) is equal to k*2^(k+2)
回答 (1)
2016-12-01 8:04 pm
take out the HCF
(k+1)*2^(k+1) +(k-1)*2^(k+1)= [(k+1) +(k-1)]*2^(k+1)=(2k)*2^(k+1) = k*2^(k+2)
(k+1)*2^(k+1) +(k-1)*2^(k+1)= [(k+1) +(k-1)]*2^(k+1)=(2k)*2^(k+1) = k*2^(k+2)
收錄日期: 2021-04-23 23:55:50
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https://hk.answers.yahoo.com/question/index?qid=20161201120041AATDmwu