Solve log½(x - 3) = -4?

2016-11-28 3:31 pm

回答 (4)

2016-11-28 3:43 pm
log(1/2)[x-3]=-4
=>
x-3=(1/2)^(-4)
=>
x-3=1/2^(-4)
=>
x-3=2^4
=>
x=16+3
=>
x=19
2016-11-28 3:42 pm
take antilog base ½ of both sides
2016-11-28 3:34 pm
log½(x - 3) = -4

Log to base 1/2 ?

x - 3 = (1/2)^-4

= 2^4

x = 16 + 3

= 19


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