更新1:
g(z)=z^2/1+z^2 怎麼算最大最小值?
g(z)=z^2/1+z^2 怎麼算最大最小值?
回答 (2)
2016-11-28 10:00 am
Sol
p=z^2/(1+z^2)
p+pz^2=z^2
(1－p)z^2=p
z^2=p/(1－p)
z^2>=0
p/(1－p)>=0，p<>1
p(1－p)>=0，p<>1
(p－1)p<=0，p<>1
0<=p<1
0<=z^2/(1=z^2)<1
p=z^2/(1+z^2)
p+pz^2=z^2
(1－p)z^2=p
z^2=p/(1－p)
z^2>=0
p/(1－p)>=0，p<>1
p(1－p)>=0，p<>1
(p－1)p<=0，p<>1
0<=p<1
0<=z^2/(1=z^2)<1
2016-11-27 6:24 pm
g(x) = x²/(1 + x²)
g(x) = (1 + x² - 1)/(1 + x²)
g(x) = 1 - 1/(1 + x²)
-∞ < x < ∞
0 ≤ x² < ∞
1 ≤ 1 + x² < ∞
0 < 1/(1 + x²) ≤ 1
-1 ≤ -1/(1 + x²) < 0
0 ≤ 1 - 1/(1 + x²) < 1
0 ≤ g(x) < 1
g(x) = (1 + x² - 1)/(1 + x²)
g(x) = 1 - 1/(1 + x²)
-∞ < x < ∞
0 ≤ x² < ∞
1 ≤ 1 + x² < ∞
0 < 1/(1 + x²) ≤ 1
-1 ≤ -1/(1 + x²) < 0
0 ≤ 1 - 1/(1 + x²) < 1
0 ≤ g(x) < 1
收錄日期: 2021-04-30 21:56:59
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20161127082707AAB7NWu