更新1:
This is a question given in NSO-24th Nov 2016
0.2 moles of the chloride of a element U reacts with excess of silver nitrate to form 57.4g of silver chloride.The formula of Chloride is?
回答 (2)
2016-11-27 5:21 am
Molar mass of AgCl = (107.9 + 35.5) g/mol = 143.4 g/mol
Ag⁺(aq) + Cl⁻(aq) → AgCl(s)
OR: Mole ratio Cl⁻ : AgCl = 1 : 1
No. of moles of AgCl = (57.4 g) / (143.4 g/mol) = 0.4 mol
No. of moles of Cl⁻ = 0.4 mol
0.2 mole of the chloride of U contains 0.4 mole of chloride ions.
Hence, 1 mole of the chloride of U contains 0.4/0.2 = 2 moles of chloride ions.
The formula of the chloride of U: UCl₂
Ag⁺(aq) + Cl⁻(aq) → AgCl(s)
OR: Mole ratio Cl⁻ : AgCl = 1 : 1
No. of moles of AgCl = (57.4 g) / (143.4 g/mol) = 0.4 mol
No. of moles of Cl⁻ = 0.4 mol
0.2 mole of the chloride of U contains 0.4 mole of chloride ions.
Hence, 1 mole of the chloride of U contains 0.4/0.2 = 2 moles of chloride ions.
The formula of the chloride of U: UCl₂
2016-11-27 3:51 am
Black people
收錄日期: 2021-04-18 15:51:31
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20161126192112AAgFkjy