3cot^2x-1=0 Find all solutions of the equation in the interval [0,2pi) Write your answer in radians in terms of pi?
回答 (2)
2016-11-25 7:14 pm
3 cot²x = 1
cot²x = 1/3
tan²x = 3
tan x = ± √3
x = π/3 , 2π/3 , 4π/3 , 5π/3
cot²x = 1/3
tan²x = 3
tan x = ± √3
x = π/3 , 2π/3 , 4π/3 , 5π/3
2016-11-25 7:09 pm
3 cot²x − 1 = 0
3 cot²x = 1
cot²x = 1/3
cot x = ±1/√3
tan x = ±√3
x = π/3, 2π/3, 4π/3, 5π/3
收錄日期: 2021-04-23 23:56:13
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