Find all solutions of the equation in the interval [0,2pi) Tanθ+(Sq rt 3)=0 Write answer in radians in terms of pi?
回答 (2)
2016-11-25 7:41 pm
tan Ө = - √3
Ө = 2π/3 , 5π/3
Ө = 2π/3 , 5π/3
2016-11-25 6:56 pm
tanθ + √3 = 0
tanθ = -√3
θ = 2π/3, 5π/3
tanθ = -√3
θ = 2π/3, 5π/3
收錄日期: 2021-04-23 23:53:07
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