When 25g of KClO3 decomposes how many L of O2 gas are formed at STP?
2KClO3(s)-->2KCl(s)+3O2(g)
回答 (1)
(25 g KClO3) / (122.5495 g KClO3/mol) x (3 mol O2 / 2 mol KClO3) x (22.414 L/mol) = 6.9 L O2 at STP
收錄日期: 2021-04-23 23:48:30
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