why does fluothane,CF3CHBrCl, does not undergo elimination with hot ethanolic NaOH?

The three F atoms are attached to the same C atom. To undergo elimination, at least one of the C-F bonds should be broken.

It is found that smaller atoms form strong bonds. As F atom is very small, C-F bond is very strong and hardly to break.

When CF₃-CHBrCl is heated with alcoholic NaOH, no elimination occurs because the three C-F bonds are hardly to break.