What is the concentration in ppm of Pb in 6.58 x 10^-3 moles Pb(NO3)2 per liter of solution? Show your work please.?

Molar mass of Pb(NO₃)₂ = (207.2 + 14.0×2 + 16.0×6) g/mol = 331.2 g/mol
Mass of Pb(NO₃)₂ in the solution = (6.58 × 10⁻³ mol) × (331.2 g/mol) = 2.18 g

As the solution is very dilute, the density of the solution ≈ the density of water = 1000 g/L
Mass of the solution = (1000 g/L) × (1 L) = 1000 g

Concentration of Pb(NO₃)₂ = (2.18/1000) × 1000000 ppm = 2180 ppm