If the product of twice a number decreased by five and five times a number increased by seven is zero; find the numbers.?

To much thinking. ...You'd be dead, before you ever had to slap leather. But I guess "jedi mind ef'n" is the new "education".. Sounds like you're dealing with some profound, "caution contents are hot" stuff right there! I'm willing to bet, you're "educated" enough to know, I have no answer.

2(n - 5)5(n + 7) = 0
n^2 + 2n - 35 = 0
(n + 7)(n - 5) = 0
5 is the number.