What is the angular momentum, about(0,0), of a 509.0g particle travel at 4.62 m/s in the +x direction, when it is at position(1.11m, 4.33m)?

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2016-11-22 6:59 pm

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What is the magnitude of the angular momentum, about the origin, of a 509.0g particle travelling at 4.62 m/s in the +x direction, when it is at position (x,y)=(1.11m, 4.33m)?

回答 (1)

Randy P

2016-11-22 7:05 pm

by definition angular momentum is r x mv. You know the position vector r, you know the momentum vector mv, and you know the formula for cross product. So what else do you need to know?

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