solve this simultaneous urgentl please! x^2-y^2 =40.....(1) and x+) =10.....(ii)?

x² - y² = 40
⇒ (x+y)(x-y) = 40
⇒ 10(x-y) = 40
⇒ x-y = 4

[1] x+y = 10
[2] x-y = 4

[1]+[2]: 2x = 14 ⇒ x = 7 ⇒ y = 3

So x = 7, y = 3.

[PSA: Don’t forget to award best answer and reclaim 3 easy points!]

x = 7, y = 3