1 (a+b)(a+2b)(a+3b)(a+4b)+b的4次方 2 X的8次方+64Y的8次方 3 X的3次方+3X的2次方+3X-7?
回答 (1)
2016-11-19 9:26 am
1 (a+b)(a+2b)(a+3b)(a+4b)+b^4
=(a+b)(a+4b)(a+2b)(a+3b)+b^4
=(a^2+5ab+4b^2)(a^2+5ab+6b^2)+b^4
=(a^2+5ab)^2+10b^2(^2+5ab)+25b^4
=(a^2+5ab+5b^2)^2
2 x^8+64y^8
=(x^4)^2+16x^4y^4+(8y^4)^2－16x^4y^4
=(x^4+8y^4)^2－(4x^2y^2)^2
=(x^4－4x^2y^2+8y^4)(x^4+4x^2y^2+8y^4)
3 x^3+3x^2+3x－7
=(x^3－x^2)+(4x^2－4x)+(7x－7)
=x^2(x－1)+4x(x－1)+7(x－1)
=(x^2+4x+7)(x－1)
=(a+b)(a+4b)(a+2b)(a+3b)+b^4
=(a^2+5ab+4b^2)(a^2+5ab+6b^2)+b^4
=(a^2+5ab)^2+10b^2(^2+5ab)+25b^4
=(a^2+5ab+5b^2)^2
2 x^8+64y^8
=(x^4)^2+16x^4y^4+(8y^4)^2－16x^4y^4
=(x^4+8y^4)^2－(4x^2y^2)^2
=(x^4－4x^2y^2+8y^4)(x^4+4x^2y^2+8y^4)
3 x^3+3x^2+3x－7
=(x^3－x^2)+(4x^2－4x)+(7x－7)
=x^2(x－1)+4x(x－1)+7(x－1)
=(x^2+4x+7)(x－1)
收錄日期: 2021-04-30 21:57:08
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20161118235916AAhzEUu