If f(x)=2x^2 -3?

Hello,

we have:

f(x) = 2x² - 3

then:


A) f(c) = 2(c)² - 3 = 2c² - 3


B) f(x + h) = 2(x + h)² - 3 = 2(x² + 2xh + h²) - 3 = 2x² + 4xh + 2h² - 3


C) [f(x + h) - f(x)] /h = [(2x² + 4xh + 2h² - 3) - (2x² - 3)] /h =
(2x² + 4xh + 2h² - 3 - 2x² + 3) /h =
(4xh + 2h²) /h =
(factorng out h and simplifying)
h (4x + 2h) /h =

4x + 2h


I hope it helps

A) f(c)2(c^2)-3
b)f(x+h)=2(x+h)^2-3=2(x^2+2xh+h^2)-3=2x^2+4xh+2h^2-3)
c)(2x^2+4xh+2h^-3)-((2x^2-3) )/3
(2x^2+4xh+2h^2-3-2x^2+3)/h=(4xh+2h^2)/h=
2h(2x+h)/h=2(2x+h)

f(x) = 2x^2 - 3
A)
f(c) = 2c^2 - 3
B)
f(x + h) = 2(x + h)^2 - 3
C)
[f(x + h) - f(x)] / h
= [2(x + h)^2 - 3 - (2x^2 - 3)] / h
= 4x + 2h
= 2(h + x)

Idk ffgg