在梯形ABCD中,A(3 , -1),B(1 , -3),C(4 , 1),若線段AD平行線段BC且線段AD=3,則D點座標為何?

2016-11-16 3:51 pm

回答 (1)

2016-11-17 2:56 am
✔ 最佳答案
Sol
設D(x,y)
(x-3)^2+(y+1)^2=9
(x-3):(y+1)=(4-1):(1+3)=3:4
4x-12=3y+3
(x-3)^2+(y+1)^2=9
(3x-9)^2+(3y+3)^2=81
(3x-9)^2+(4x-12)^2=81
9(x-3)^2+16(x-3)^2=81
25(x-3)^2=81
(x-3)^2=81/25
X-3=9/5 or x-3=-9/5
x=24/5 or x=6/5(不合)
3y+3=96/5-12
3y+3=36/5
y+1=12/5
y=7/5
D(24/5,7/5)


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