函數及其圖像(5) 吾係太識做,吾亥幫忙教育我做?

2016-11-16 1:22 pm

回答 (1)

2016-11-17 4:54 am
✔ 最佳答案
1
y=x^2+2x+2
=(x^2+2x+1)+1
=(x+1)^2+1
(x+1)^2>=0
(x+1)^2+1>=1
y>=1
極小
2
y=x^2+2x-5
=(x^2+2x+1)-6
=(x+1)^2-6
(x+1)^2>=0
(x+1)^2-6>=-6
y>=-6
極小
3
y=x^2+6x+8
=(x^2+6x+9)-1
=(x+3)^2-1
(x+3)^2>=0
(x+3)^2-1>=-1
y>=-1
極小
4
y=x^2-4x-8
=(x^2-4x+4)-12
=(x-2)^2-12
(x-2)^2>=0
(x-2)^2-12>=-12
y>=-12
極小
5
y=-x^2-2x-4
=-(x^2+2x+1)-3
=-(x+1)^2--
(x+1)^2>=0
-(x+1)^2<=0
-(x+1)^2-3<=-3
y<=-3
極大
6
y=-x^2-8x+1
=-(x^2+8x+16)+17
=-(x+4)^2+17
(x+4)^2>=0
-(x+4)^2<=0
-(x+4)^2+17<=17
y<=17
極大


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