0.1 M 的 CO2 = 多少PPM 又如何能稀釋成 100 ppm 要添加多少?
回答 (1)
2016-11-16 8:23 am
1ppm=1mg/L
0.1MCO2=0.1mol CO2 per dm^3
1L=1000cm^3,1dm=10cm
0.1/1000=1x10^-4mol/L
molar mass of C02=44g/mol
(1x10^-4)x44=4.4x10^-3g/L=4.4mg/L=4.4ppm
for 100ppm=100mg/L=0.1g/L
0.1/44=2.27x10^-3mol/L
no. of CO2 needed=(2.27x10^-3)-(1x10^-4)=2.17x10^-3mol/L
(2.17x10^-3)x1000=2.17mol
thus, add 2.17mol CO2 to give 100ppm
0.1MCO2=0.1mol CO2 per dm^3
1L=1000cm^3,1dm=10cm
0.1/1000=1x10^-4mol/L
molar mass of C02=44g/mol
(1x10^-4)x44=4.4x10^-3g/L=4.4mg/L=4.4ppm
for 100ppm=100mg/L=0.1g/L
0.1/44=2.27x10^-3mol/L
no. of CO2 needed=(2.27x10^-3)-(1x10^-4)=2.17x10^-3mol/L
(2.17x10^-3)x1000=2.17mol
thus, add 2.17mol CO2 to give 100ppm
收錄日期: 2021-04-18 15:46:14
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20161115192243AARr2Uw