how many moles of NO2 form when ea amt of reactant completely reacts 2N2O5(g)→4NO2(g)+O2(g) 5.26×103molN2O5 use 3 significant figures.?
回答 (1)
2016-11-13 3:36 pm
2N₂O₅(g) → 4NO₂(g) + O₂(g)
OR: Mole ratio N₂O₅ : NO₂ = 2 : 4 = 1 : 2
No. of moles of N₂O₅ reacted = 5.26 × 10³ mol
No. of moles of NO₂ formed = (5.26 × 10³ mol) × 2 = 1.05 × 10⁴ mol
OR: Mole ratio N₂O₅ : NO₂ = 2 : 4 = 1 : 2
No. of moles of N₂O₅ reacted = 5.26 × 10³ mol
No. of moles of NO₂ formed = (5.26 × 10³ mol) × 2 = 1.05 × 10⁴ mol
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