Find the gradient of the curve f(X)=2x^2-5x+3 at the point where it cuts the y-axis?
回答 (3)
2016-11-12 1:39 pm
f(x) = 2x^2-5x+3
f'(x) = 4x-5
At the point where the urve cuts the y-axis, x=0
f'(0)= 4(0)-5 = -5
f'(x) = 4x-5
At the point where the urve cuts the y-axis, x=0
f'(0)= 4(0)-5 = -5
2016-11-12 1:30 pm
f ` (x) = 4x - 5
f ` (0) = - 5
f ` (0) = - 5
2016-11-12 1:01 pm
At the y-axis, x = 0.
f '(x) = 4x - 4
f '(0) = 4(0) - 4 = -4
f '(x) = 4x - 4
f '(0) = 4(0) - 4 = -4
收錄日期: 2021-04-22 00:03:34
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20161112045931AAnXZfL